Application Hints (Continued)
SHUNT CAPACITANCE
In certain applications, the 15 pF shunt capacitance of the
LM134 may have to be reduced, either because of loading
problems or because it limits the AC output impedance of
the current source. This can be easily accomplished by buff-
ering the LM134 with an FET as shown in the applications.
This can reduce capacitance to less than 3 pF and improve
regulation by at least an order of magnitude. DC character-
istics (with the exception of minimum input voltage), are not
affected.
NOISE
Current noise generated by the LM134 is approximately 4
times the shot noise of a transistor. If the LM134 is used as
an active load for a transistor amplifier, input referred noise
will be increased by about 12 dB. In many cases, this is
acceptable and a single stage amplifier can be built with a
voltage gain exceeding 2000.
LEAD RESISTANCE
The sense voltage which determines operating current of
the LM134 is less than 100 mV. At this level, thermocouple
or lead resistance effects should be minimized by locating
the current setting resistor physically close to the device.
Sockets should be avoided if possible. It takes only 0.7X
contact resistance to reduce output current by 1% at the
1 mA level.
SENSING TEMPERATURE
The LM134 makes an ideal remote temperature sensor be-
cause its current mode operation does not lose accuracy
over long wire runs. Output current is directly proportional to
absolute temperature in degrees Kelvin, according to the
following formula:
ISET e(227 mV/§K) (T)
RSET
Calibration of the LM134 is greatly simplified because of the
fact that most of the initial inaccuracy is due to a gain term
(slope error) and not an offset. This means that a calibration
consisting of a gain adjustment only will trim both slope and
zero at the same time. In addition, gain adjustment is a one
point trim because the output of the LM134 extrapolates to
zero at 0§K, independent of RSET or any initial inaccuracy.
TL/H/5697– 4
FIGURE 2. Gain Adjustment
This property of the LM134 is illustrated in the accompany-
ing graph. Line abc is the sensor current before trimming.
Line aÊbÊcÊis the desired output. A gain trim done at T2 will
move the output from b to bÊand will simultaneously correct
the slope so that the output at T1 and T3 will be correct.
This gain trim can be done on RSET or on the load resistor
used to terminate the LM134. Slope error after trim will nor-
mally be less than g1%. To maintain this accuracy, howev-
er, a low temperature coefficient resistor must be used for
RSET.
A 33 ppm/§C drift of RSET will give a 1% slope error be-
cause the resistor will normally see about the same temper-
ature variations as the LM134. Separating RSET from the
LM134 requires 3 wires and has lead resistance problems,
so is not normally recommended. Metal film resistors with
less than 20 ppm/§C drift are readily available. Wire wound
resistors may also be used where best stability is required.
APPLICATION AS A ZERO TEMPERATURE
COEFFICENT CURRENT SOURCE
Adding a diode and a resistor to the standard LM134 config-
uration can cancel the temperature-dependent characteris-
tic of the LM134. The circuit shown in
Figure 3
balances the
positive tempco of the LM134 (about a0.23 mV/§C) with
the negative tempco of a forward-biased silicon diode
(about b2.5 mV/§C).
TL/H/5697– 28
FIGURE 3. Zero Tempco Current Source
The set current (ISET) is the sum of I1and I2, each contribut-
ing approximately 50% of the set current, and IBIAS.I
BIAS is
usually included in the I1term by increasing the VRvalue
used for calculations by 5.9%. (See CALCULATING RSET.)
ISET eI1aI2aIBIAS, where
I1eVR
R1
and I2eVRaVD
R2
The first step is to minimize the tempco of the circuit, using
the following equations. An example is given using a value
of a227 mV/§C as the tempco of the LM134 (which in-
cludes the IBIAS component), and b2.5 mV/§C as the temp-
co of the diode (for best results, this value should be directly
measured or obtained from the manufacturer of the diode).
ISET eI1aI2
dISET
dT edI1
dT adI2
dT
&227 mV/§C
R1
a227 mV/§Cb2.5 mV/§C
R2
e0 (solve for tempco e0)
5